30x^2+67x-20=0

Solution for 30x^2+67x-20=0 equation:

30x^2+67x-20=0

a = 30; b = 67; c = -20;
Δ = b2-4ac
Δ = 672-4·30·(-20)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-83}{2*30}=\frac{-150}{60}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+83}{2*30}=\frac{16}{60}
=4/15
$